When `3.2gm` of sulphur is vapourised,it gives `280ml` of vapour at `273^(@)C` and `1520mm` pressure.Molecular formula of sulphur is

3.2 g of S is heated to occupy a volume of 780 ml at 450^(@)C and 723 mm pressure. Formula of sulphure is

When 3.2g of sulphur is vapourised at 450^(@)C and 723 mm pressure , the vapours occupy a volume of 780ml. What is the molecular formula of sulphur vapours under these conditions? Calculate the vapour density also.

When 3.2 gm of sulphur is vapourized at 450^(@)C and 723 mm pressure, the vapour occupies a volume of 780 m, what is the formula for the sulphur under these conditions?

When 3.2g sulphur is vaporised at 450^(@)C and 723mmHg pressure,the vapours occupy a volume of 780ml what is the molecular formula of S-vapour

5g sulphur is present in 100 g of CS_(2). DeltaT_(b) of solution 0.954 and K_(b) is 4.88. The molecular formula of sulphur is

0.1693 gm of a volatile substance when vapourised displaced 58.9 cm of air measured at 27^@C and 746 mm pressure. Calculate the molecular mass of the substance. (Aqueous tenstion at 27^@C=26.7mmHg .)

280 mL of sulphur vapour (S_(x) at 1 atm , 273 K weighs 1.6 gm . Determine the molecular formula of sulphur vapour?