Alternating voltage (V) is represented by the equation
whrere `V_(m)` is the peak voltage

An alternating voltage is represented by V = 240 sin 100 πt V. Find the peak voltage, rms voltage, frequency of the source.

If an alternating voltage is represented as v = 300 sin 600 t then the arms value of the voltage and the frequency are respectively :

If an alternating voltage is represented as v = 300 sin 600 t then the arms value of the voltage and the frequency are respectively :

If an alternating voltage is represented as E = 141 sin (628t) , then (1) the rms voltage is 141V (2) the rms voltage is 100V (3) the frequency is 50 Hz (4) the frequency is 100 Hz

An alternating voltage is represented by V=80 sin(100 pi t)cos(100 pi t) volt, What is the peak voltage?

If the voltage in an ac circuit is represented by the equation. V = 220 sqrt(2) sin (314 t - phi) volt calculate (a) peak and rms value of the voltage, (b) average voltage, (c) frequency of ac .

An alternating voltage is represented by E=311sin(100pit-pi/6)V Determine its frequency, time period , peak value and rms value.

In a full wave rectifiers in which input voltage is represented by V=V_(M)sin omegat , then peak inversion voltage of non-conducting diode will be

In a full wave rectifiers in which input voltage is represented by V=V_(M)sin omegat , then peak inversion voltage of non-conducting diode will be

If the voltage in an ac circuit is represented by the equation, V= 220sqrt2 sin(314t-phi) V. Calculate (a) peak and rms.value of the voltage (b) average voltage (c) frequency of AC