" (ii) "sqrt(2)+(1)/(sqrt(2))+(1)/(2sqrt(2))+..." to "8" terms; "

(3)/(sqrt(8))+(1)/(sqrt(2))

Find the sum of the GP: (i) 1+3+9+27+... to 7 terms (ii) 1+sqrt(3)+3+3sqrt(3)+... to 10 terms (iii) 0.15+0.015+0.0015+... to 6 terms (iv) 1-1/2+1/4-1/8+... to 9 terms (v) sqrt(2)+1/sqrt(2)+1/(2sqrt(2))+... to 8 terms (vi) 2/9-1/3+1/2-3/4+... to 6 terms

Find the sum of the following geometric series: sqrt(2)+(1)/(sqrt(2))+(1)/(2sqrt(2))+rarr8 terms

(sqrt(2)+7)/(sqrt(2)-1)+sqrt(8)

(sqrt(?)-1)^(2)=8-sqrt(28)

The sum of infinite terms of the geometric progression (sqrt(2)+1)/(sqrt(2)-1),(1)/(2-sqrt(2)),(1)/(2),... is

The sum of infinite terms of the geometric progression (sqrt(2) + 1)/(sqrt(2) - 1) , 1/(2 - sqrt(2)) , 1/2 ....... Is

(1)/(sqrt(8+2+sqrt(15)))=