If `C` is the center and `A, B` are two points on the conic `4x^2+9y^2-8x-36y+4=0` such that `/_ACB=90^@` then prove that `1/(CA)^2+1/(CB)^2=13/36`

If C is the center and A ,B are two points on the conic 4x^2+9y^2-8x-36 y+4=0 such that /_A C B=pi/2, then prove that 1/(C A^2)+1/(C B^2)=(13)/(36)dot

If C is the center and A ,B are two points on the conic 4x^2+9y^2-8x-36 y+4=0 such that /_A C B=pi/2, then prove that 1/(C A^2)+1/(C B^2)=(13)/(36)dot

If C is the center and A ,B are two points on the conic 4x^2+9y^2-8x-36 y+4=0 such that /_A C B=pi/2, then prove that 1/(C A^2)+1/(C B^2)=(13)/(36)dot

If C is the center and A,B are two points on the conic 4x^(2)+9y^(2)-8x-36y+4=0 such that /_ACB=(pi)/(2), then prove that (1)/(CA^(2))+(1)/(CB^(2))=(13)/(36) .

C is the centre of the ellipse x^(2)/16+y^(2)/9=1 and A and B are two points on the ellipse such that /_ACB=90^@ , then 1/(CA)^(2)+1/((CB)^(2))=

C is the centre of the ellipse x^(2)/16+y^(2)/9=1 and A and B are two points on the ellipse such that /_ACB=90^@ , then 1/(CA)^(2)+1/((CB)^(2))=

C is the centre of the ellipse x^(2)/16+y^(2)/9=1 and A and B are two points on the ellipse such that angle ACB=90◦, then 1/(CA)^(2)+1/((CB)^(2))=

Consider the conic find 9y^2-4x^2=36 The foci.

Find the eccentricity of the ellipse, 4x^(2)+9y^(2)-8x-36y+4=0 .