In the expansion of `(7^(1/3)+11^(1/9))^(6561)`, the number of terms free from radicals is:

If the expansion of (y^(1//2)+x^(1//3))^(54) , the number of terms free from radical sign (number of rational terms) are independent where |x| and |y| have no common factor except 1 annd x,y ne Q, is (1) 9 (2) 8 (3) 10 (4) 11.

In the expansion of (y^(1//5)+x^(1//10))^55 , the number of terms free of radical sign are

In the expansion of (y^(1//5)+x^(1//10))^55 , the number of terms free of radical sign are

In the expansion of (2sqrt(2)+root4(7))^(100) the number of the term free from radical sign is …………

The number of terms in the expansion of (1+x^(1/5))^55 which are free from radicals is _____.

In the expansion of (7^(1//3)+11^(1//9))^(6561) , (a)there are exactly 730 rational term (b)there are exactly 5831 irrational terms (c)the term which involves greatest binomial coefficients is irrational (d)the term which involves greatest binomial coefficients is rational

In the expansion of (7^(1/3)+11^(1/9))^(6561) (a)there are exactly 730 rational term (bthere are exactly 5831 irrational term (bthe term which involves greatest binomial coefficients is irrational (d)the term which involves greatest binomial coefficients is rational

If the number of terms free from radicals in the expansion of (7^((1)/(3))+11^((1)/(9)))^(6561) is k, then the value of (k)/(100) is equal to

If the number of terms free from radicals in the expansion of (7^((1)/(3))+11^((1)/(9)))^(6561) is k, then the value of (k)/(100) is equal to