The parabola `x^2 = py` passes through `(12,16)`.Then the focal distance of the point is

If the parabola y^(2) = 4ax passes through the point (4, 1), then the distance of its focus the vertex of the parabola is

If the parabola y^(2) = 4ax passes through the point (4, 1), then the distance of its focus the vertex of the parabola is

If the parabola y^(2)=ax passes through (1,2) then the equation of the directrix is

If (-2,5) and (3,7) are the points of intersection of the tangent and normal at a point on a parabola with the axis of the parabola, then the focal distance of that point is

If (-2,5) and (3,7) are the points of intersection of the tangent and normal at a point on a parabola with the axis of the parabola, then the focal distance of that point is

The parabola x^(2) +2py = 0 passes through the point (4,-2) , find the coordinates of focus and the length of latus rectum .

The parabola x^(2)+2py=0 passes through the point (4,-2); find the co-ordinates of focus and the length of latus rectum.

I : The length of the latus rectum of the parabola y^(2)+8x-2y+17=0 is 8 . II: The focal distance of the point (9,6) on the parabola y^(2)=4x is 12

If theta is the angle between the tangents to the parabola y^(2)=12x passing through the point (-1,2) then |tan theta| is equal to