if `tan^-1(1/(1+1*2))+tan^-1(1/(1+2*3))+.............+tan^-1(1/(1+n*(n+1)))=tan^-1theta` then find the value of `theta`

If tan^(-1)(1/(1+1. 2))+tan^(-1)(1/(1+2. 3))+.... +tan^(-1)(1/(1+n.(n+1)))=tan^(-1)theta, then find the value of thetadot

tan^(-1)((1)/(1+1.2))+tan^(-1)((1)/(1)+2.3)+...+tan^(-1)((1)/(1+n(n+1)))=tan^(-1)theta then find the value of theta.

tan^-1 (1/(1+2))+tan^-1(1/(1+(2)(3)))tan^-1(1/(1+(3)(4)))+...tan^-1(1/(1+n(n+1)))=tan^-1 theta

tan^(-1)(1/2)+tan^(-1)(1/3)=tan^(-1)(theta) then theta is

(tan^(-1)((1)/(3))+tan^(-1)((1)/(7))+tan^(-1)((1)/(13))+......+tan^(-1)((1)/(381)))=(m)/(n) where m,n in N, then find least value of (m+n)

If 2tan^(-1)(cos theta)=tan^(-1)(2csc theta),(theta!=0), then find the value of theta.

If "Tan"^(-1)1/(1+2)+"Tan"^(-1)1/(1+(2)(3))+"Tan"^(-1)1/(1+(3)(4))+..."Tan"^(-1)1/(1+n(n+1))=Tan^(-1)theta , then theta =

If (1+ tan theta) (1+ tan phi)=2, then the value of (theta+ phi) is