`x :sin^(- 1)(2alpha)/(1+a^2)+sin^(- 1)(2beta)/(1+beta^2)=2tan^(- 1)x`

Solve : sin^(-1)((2alpha)/(1+alpha^2)) + sin^(-1)( (2beta)/(1+beta^2)) =2 tan^(-1) x, |alpha|le1, |beta|le1

Solve : sin^(-1)((2alpha)/(1+alpha^2)) + sin^(-1)( (2beta)/(1+beta^2)) =2 tan^(-1) x, |alpha|le1, |beta|le1

Solve for x, "sin"^(-1)((2alpha)/(1+alpha^(2)))+"sin"^(-1)((2beta)/(1+beta^(2)))=2"tan"^(-1)x .

Prove that 2tan^(-1)[tan((alpha)/(2)) tan((pi)/(4)-(beta)/(2))]=tan^(-1)((sin alpha cos beta)/(cos alpha+sin beta))

Show taht 2tan ^ (- 1) (tan ((alpha) / (2)) tan ((pi) / (4) - (beta) / (2))) = tan ^ (- 1) ((sin alpha cos beta) / (cos alpha + sin beta))

Prove that: (alpha^(3))/(2)csc^(2)((1)/(2)tan^(-1)(alpha)/(beta))+(beta^(2))/(2)sec^(2)((1)/(2)tan^(-1)(beta)/(alpha))=(alpha+beta)(a^(2)+beta^(2))

If alpha and beta are the roots of the equation x^(2)-4x+1=0(alpha>beta) then find the value of f(alpha,beta)=(beta^(3))/(2)csc^(2)((1)/(2)tan^(-1)((beta)/(alpha))+(alpha^(3))/(2)sec^(2)((1)/(2)tan^(-1)((alpha)/(beta)))

If alpha and beta are the roots of the equation x^(2)-4x+1=0(alpha