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The equation of the circle the two ends ...

The equation of the circle the two ends of its diameter are (a, 2a) and (2a, a) iss

A

`x^2 + y^2 - 3ax -3ay + 4a^2 = 0`

B

`x^2 +y^2 - 12ax - 12ay + 114 a^2 = 0`

C

`x^2 + y^2 + 13 ax + 3ay - 4 a^2 = 0`

D

`x^2 + y^2 - 3ax + 3ay + 4a^2 = 0`

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A
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KCET PREVIOUS YEAR PAPERS-MODEL TEST PAPER - 1-MATHEMATICS
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