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The permittivity of free space epsi0=8.8...

The permittivity of free space `epsi_0=8.86 xx 10^(-12)` coulomb/`N-m^2` and the permeability of the free space `mu_0 = 1.26 xx 10^(-6)` henry/metre. If c is the velocity of light in vacuum, the correct relation between `mu^0,epsi_0` and c is

A

`mu_0c^2 = epsi_0`

B

`mu_0epsi_0 = 1//c^2`

C

`mu_0epsi^2 = c^2`

D

`mu_0 epsi_0 = 1//c`

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The correct Answer is:
B
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