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Obtain the value of specific heat of wat...

Obtain the value of specific heat of water in terms of `Jkg^(-1)K^(-1)`.

A

45°C

B

50°C

C

55°C

D

35°C

Text Solution

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The correct Answer is:
B
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A copper block of mass 2.5 kg ts heated in a furnace to a temperature of 500 ^(@) C and then placed on a large ice block. What is the maximum amount of ice that can melt? (Specific heat of copper = 0.39 J g^(-1) K^(-1), " heat of fusion of water " = 335 J g^(-1)) .

Find the amount of heat required to convert 10 kg ice at -10^(@)C to water at 50^(@)C . Given specific heat of ice 2100Jkg^(-1)K^(-1) , specific heat of water 4200Jkg^(-1)K^(-1) and latent heat of ice 3.36xx10^5Jkg^(-1)

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Calculate the heat required to convert 3 kg of ice at -12 ^(@) C kept in a calorimeter to steam at 100^(@) C at atmospheric pressure. Given specific heat capacity of ice = 2100 J kg^(-1) K^(-1) , specific heat capacity of water = 4186 J kg^(-1) K^(-1) , latent heat of fusion of ice = 3.35 xx 10^(5) J kg^(-1) and latent heat of steam = 2.256 xx 10^(8) J kg^(-1) .

KCET PREVIOUS YEAR PAPERS-MODEL TEST PAPER 3-(PHYSICS)
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