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An electron of mass m, when accelerated ...

An electron of mass `m`, when accelerated through a potential difference `V`, has de Broglie wavelength `lambda`. The de Broglie wavelength associated with a proton of mass `M`, accelerated through the same potential difference, will be

A

`lambda(M/m)`

B

`lambda` `sqrt(M/m)`

C

`lambda(m/M)`

D

`lambda sqrt(m/M)`

Text Solution

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The correct Answer is:
D
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