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If costheta=((acosphi+b))/((a+bcosphi)),...

If `costheta=((acosphi+b))/((a+bcosphi))`, then the value of tan `(theta//2)` is equal to

A

`sqrt((a-b)/(a+b))"tan"(phi)/(2)`

B

`sqrt((a+b)/(a-b))"tan"(phi)/(2)`

C

`sqrt((a-b)/(a+b))"cos"(phi)/(2)`

D

`sqrt((a+b)/(a-b))"sin"(phi)/(2)`.

Text Solution

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The correct Answer is:
A
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