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If `[vec(a),vec(b),vec(c)]` denotes the scalar triple product of the vectors `vec(a),vec(b),vec(c)`, then `[vec(a)+vec(b),vec(b)+vec(c),vec(c)+vec(a)]` is equal to

A

0

B

`[vec(a),vec(b),vec(c)]`

C

`3[vec(a),vec(b),vec(c)]`

D

`2[vec(a),vec(b),vec(c)]`

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The correct Answer is:
D
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