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CH(3)C-=C CH(3)underset((ii)H(2) O //Zn)...

`CH_(3)C-=C CH_(3)underset((ii)H_(2) O //Zn)overset((i)X)(to)H_(3)C-underset(O)underset(||)(C)-underset(O)underset(||)(C)-CH_(3)`
In the above reaction X is

A

`HNO_(3)`

B

`O_(3)`

C

`O_(2)`

D

`KMnO_(4)`

Text Solution

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The correct Answer is:
B
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