A simple pendulum can be used to determine acceleration due to gravity at a given place.

Calculate the time period of a simple pendulum of length one meter. The acceleration due to gravity at the place is pi^2ms^-2 .

Calculate the time period of a simple pendulum of length one meter. The acceleration due to gravity at the place is pi^2ms^-2 .

In an experiment on simple pendulum to determine the acceleration due to gravity, a student measures the elngth of the thread as 632 cm and diameter of the pendulum bob as 2.256 cm. The student should take the lenght of the pendulum to be

Calculate the tiem period of a simple pendulum of length one meter. The acceleration due ot gravity at the place is pi^2ms^-2 .

In a simple pendulum experiment for the determination of acceleration due to gravity time period is measured with an accuracy of 0.1 % while length was measured with an accuracy of 0.3 % . the percentage accuracy in the value of g so obtained is

The time period of a simple pendulum is given by T = 2pi sqrt((l)/(g)) where 'l' is the length of the pendulum and 'g' is the acceleration due to gravity at that place. (a) Express 'g' in terms of T (b) What is the length of the seconds pendulum ? (Take g = 10 m s^(-2) )

Time period of simple pendulum of length l at a place, where acceleration due to gravity is g and period T. Then period of simple pendulum of the same length at a place where the acceleration due to gravity 1.02 g will be

The time period T of a simple pendulum depends on length L and acceleration due to gravity g Establish a relation using dimensions.