`2x+3y-5=0, 2x+3y+15=0, x+y-7=0, x+y+7=0` are sides of a parallelogram. Then the centre of the parallelogram is

If the adjacent sides of a parallelogram are 2x^(2)5x+3y^(2)=0 and one diagonal is

3x - 2y + 1 = 0 and 2x - y = 0 are the equation of the sides AB and AD of the parallelogram ABCD and the equation of a diagonal of the parallelogram is 5x - 3y - 1 = 0 . The equation of the other diagonal of the parallelogram is : (A) x-y+1=0 (B) x-y-1=0 (C) 3x+5y+13=0 (D) 3x+5y=13

The consecutive sides of a parallelogram are 4 x+5 y=0 and 7 x+2 y=0 . One diagonal of the parallelogram is 11 x+7 y=9 . If the other diagonal is a x+b y+c=0, then

Two consecutive sides of a parallelogram are 4x + 5y = 0 and 7x + 2y = 0. One diagonal of the parallelogram is 11x+7y=9. If the other diagonal is ax + by + c = 0, then

Two adjacent sides of a parallelogram are 4x+5y=0 ,and 7x+2y=0 . If the equation of one diagonal is 11x+7y=9 Area of the parallelogram is

Two adjacent sides of a parallelogram are 4x + 5y = 0 and 7x + 2y = 0 . if the equation of it's one diagonal be 11x +7y = 9 , Area of parallelogram is

Consider a parallelogram whose sides are represented by the lines 2x+3y=0,2x+3y-5=0,3x-4y=0 and 3x-4y=3. The equation of the diagonal not passing through the origin is

If the planes 2x + 3y - z + 5 = 0, x + 2y – kz + 7 = 0 are perpendicular then k=

The consecutive sides of a parallelogram are 4x + 5y = 0 and 7x + 2y = 0. If the equation of one of the diagonals is 11 x + 7y = 9, find the equation of the other diagonal.