8z^(2)-24z+1z-3

Find the quotient and remainder of the following : ( - 18z + 14z^(2) + 24z^(3) +18 ) div ( 37 + 4 )

4z ^(2)- 8z + 3= ?

int(3z^(3)-8z+5)/(sqrt(z^(2)-4z-7))dz=(z^(2)+az+36)sqrt(z^(2)-4z-7)+b ln|z-2+sqrt(z^(2)-4z-7)| where a,b in I and C is integretion constant,then

If |z+3|^(2)-|z-3|^(2)=8 then the locus of z is

If z^(2)-z+1=0, then the value of (1)/(12)[(z+(1)/(z))^(2)+(z^(2)+(1)/(z^(2)))^(2)+(z^(3)+(1)/(z^(3)))^(2)+.........(x^(24)+(1)/(z^(24)))^(2)] is equal to

If |z_(1)|=1,|z_(2)|=2,|z_(3)|=3 ,then |z_(1)+z_(2)+z_(3)|^(2)+|-z_(1)+z_(2)+z_(3)|^(2)+|z_(1)-z_(2)+z_(3)|^(2)+|z_(1)+z_(2)-z_(3)|^(2) is equal to

If z= -3 + sqrt2i , then prove that z^(4) + 5z^(3) + 8z^(2) + 7z + 4 is equal to -29

Subtract : 3z^(2)-2z^(2)+7z -8 from 8-z-z^(2)

If z = 2 + i, prove that z^(3) + 3z^(2) - 9z + 8 = (1 + 14i) .