[" Equation of tangent to "y^(2)=8x" which is "],[" parallel to "x-y+3=0" is "]

Find the equation of tangent to the curve x^(2)=y which is parallel to the line 2x-y+3=0

The equation of one of the tangents to x^2/3-y^2/2=1 which is parallel to y = x is :

The equation of the tangent to the parabola y^(2)=8x and which is parallel to the line x-y+3=0 is

The equation of the tangent to the parabola y^(2)=8x and which is parallel to the line x-y+3=0 is

The equation of the tangent to the parabola y^(2) = 8x, which is parallel to the line 2x-y+7=0 ,will be

Equation of the tangent of 3x^(2)+4y^(2)=12 ,parallel to x-2y+1=0 is

Find the equation of the tangent to the parabola y^(2) = 8x which is parallel to the line 2x + 2y + 5 = 0 . Find its point of contact.

The equation of the normal to the curve 3x^2-y^2=8 which is parallel to x+3y=8 is x-3y=8 (b) x-3y+8=0 (c) x+3y+-8=0 (d) x+3y=0