[int2x-5y+4=0],[2x+y-8=0]

The pair of equations 2x-5y+4=0 and 2x+y-8=0 has

Solve: {:(2x - 5y + 4 = 0),(2x + y - 8 = 0):}

The perpendicular distance of the straight line 3x + 4y- 8 = 0 from the point of intersection of the lines 3x + 2y + 4 = 0, 2x + 5y -1=0 is

The figure formed by the lines 2x-5y+4=0, 5x+2y+7=0, 2x-5y+3=0, 5x+2y-6=0 is

The figure formed by the lines 2x+5y+4=0,5x+2y+7=0,2x+5y+3=0 and 5x+2y+6=0 is

The figure formed by the lines 2x+5y+4=0, 5x+2y+7=0, 2x+5y+3=0 and 5x+2y+6=0 is

find x and y : 2x+y-5=0 3x+2y-8=0

The point of intersection of the diagonals of the rhombus formed by the lines 2x+y-5=0, x+2y+8=0, 2x+y+5=0, and x+2y-2=0 is