Home
Class 9
MATHS
In the figure ''P'' is a point in the in...

In the figure ''P'' is a point in the interior of a parallelogram ABCD.
Show that area of `DeltaAPD+` area of `DeltaPBC` = area of `DeltaAPB+` area of `DeltaPCD`.

Promotional Banner

Topper's Solved these Questions

  • GEOMETRY

    FULL MARKS|Exercise Assignment (III. Fill in the blanks )|5 Videos

  • COORDINATE GEOMETRY

    FULL MARKS|Exercise TEXTBOOK ACTIVITY|2 Videos

  • MENSURATION

    FULL MARKS|Exercise Assignment (II. Answer the following questions)|8 Videos

Similar Questions

Explore conceptually related problems

If G is the centroid of a DeltaABC," Prove that "(" area of "DeltaGAB)" "=(" area of "DeltaGBC)=( "area fo "DeltaGCA)=(1)/(3)(" area of "DeltaABC)

In the figure, find area of triangle AGF

In the figure, find area of triangle FED

Show that the diagonals of a parallelogram divide it into four triangles of equal area.

Let O be an interior point of DeltaABC such that bar(OA)+2bar(OB) + 3bar(OC) = 0 . Then the ratio of a DeltaABC to area of DeltaAOC is

Let 'P' be an interior point of Delta ABC . If angle A=45^(@), angle B=60^(@) and angle C=75^(@) . If X=area of Delta PBC,Y= area of Delta PAC and Z = area of Delta PAB , then which of the following ratios is/are true ?

What is the SI unit of Area?

In the figure, find the area of quadrilateral BCEG.

In the figure , DE || BC and (AD)/(DB) = 3/5 , calculate the value of (i) ("area of " Delta ADE)/("area of " Delta ABC) (ii) ("area of trapezium BCED")/("area of " Delta ABC)