`x^3+27`

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If 3x + (1)/(3x) = 3 , find : (ii) 27x^3 + (1)/( 27x^3)

The solution set of |4x-3|<27 is

Factorize: 8(x+y)^3-27\ (x-y)^3

If x ne 0 and 3x +(1)/(3x)= 8, find the value of :27 x^(3) + ( 1)/(27x^(3))

If (x+2)^3-27=0 then a value of x is

if f(x)=((e^((x+3)ln27))^(x/27)-9)/(3^x-27) , x 3 if lim_(x->3)f(x) exist then lmbda is

Factorize: 8(x+y)^3-27(x-y)^3

Factorize : 8(x+y)^3-27(x-y)^3