Home
Class 10
MATHS
Prove the 2^(n)+6times9^(n) is always di...

Prove the `2^(n)+6times9^(n)` is always divisible by 7 for any positive integer n.

Promotional Banner

Topper's Solved these Questions

  • NUMBERS AND SEQUENCES

    FULL MARKS|Exercise EXERCISE 2.4|6 Videos
  • NUMBERS AND SEQUENCES

    FULL MARKS|Exercise EXERCISE 2.5|14 Videos
  • NUMBERS AND SEQUENCES

    FULL MARKS|Exercise EXERCISE 2.2|8 Videos
  • MENSURATION

    FULL MARKS|Exercise ADDITIONAL QUESTIONS SOLVED (iii)|8 Videos
  • RELATIONS AND FUNCTIONS

    FULL MARKS|Exercise ADDITIONAL QUESTIONS SOLVED (ANSWER THE FOLLOWING QUESTIONS)|26 Videos

Similar Questions

Explore conceptually related problems

Prove that 7^(n) - 6n - 1 is always divisible by 36.

Prove that n^(2)-n divisible by 2 for every positive integer n.

Prove that 2.7^(n)+ 3.5^(n)-5 is divisible by 24 for all n in N

Using Binomial theorem, prove that 6^(n)-5n always leaves remainder 1 when divided by 25 for all positive integer n.

Show that one and only one out of n, n + 2 or n + 4 is divisible by 3, where n is any positive integer