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(1+tan^(2)theta)/(1+cot^(2)theta)=...

`(1+tan^(2)theta)/(1+cot^(2)theta)=`

A

`cos^(2)theta`

B

`tan^(2)theta`

C

`sin^(2)theta`

D

`cot^(2)theta`

Text Solution

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The correct Answer is:
B
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Prove that following identities (1-tan^(2)theta)/(cot^(2)theta-1)=tan^(2)theta

Prove that following identities (1-tan^(2)theta)/(cot^(2)theta-1)=tan^(2)theta

Prove that (tan^(2)theta-1)/(tan^(2)theta+1)=1-2cos^(2)theta

(1-cos^(2)theta)(1+cot^(2)theta)= ………. .

If tantheta+(1)/(tantheta)=2, then show that tan^(2)theta+(1)/(tan^(2)theta) =2.

Simplify: cos^(2)theta+(1)/(1+cot^(2)theta):

The value of (1 - cos^(2) theta) (1 + cot^(2) theta) is ……….. .

Solve tan^(2) theta+cot^(2) theta=2 .

If tan theta+cot theta=3, then tan^(2) theta+cot^(2) theta= ____.

FULL MARKS-TRIGONOMETRY-ADDITIONAL QUESTIONS SOLVED
  1. cos^(4)x-sin^(4)x=……….. .

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  2. If tantheta=a/x, then the value of x/(sqrt(a^(2)+x^(2))) =………… .

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  3. If x=asectheta,y=btantheta, then the value of x^(2)/a^(2)-y^(2)/b^(2)=...

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  4. sectheta/(cottheta+tantheta)=………… .

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  5. (sin(90^(@)-theta)sintheta)/tantheta + (cos(90^(@)-theta)costheta)/cot...

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  6. In the adjoining figure, AC = ……….. .

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  7. In the adjoining figure, / ABC = ……….. .

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  8. A man is 28.5 m away from a tower. His eye level above the ground is 1...

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  9. In the adjoining figure, sintheta=15/17. Then BC=……… .

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  10. (1+tan^(2)theta)(1-sintheta)(1+sintheta)=………… .

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  11. (1+cot^(2)theta)(1-costheta)(1+costheta)=……… .

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  12. (cos^(2)theta-1)(cot^(2)theta+1)+1=………….. .

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  13. (1+tan^(2)theta)/(1+cot^(2)theta)=

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  14. The value of sin^(2)theta+(1)/(1+tan^(2)theta) is equal to

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  15. 9tan^(2)theta-9sec^(2)theta=………… .

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  16. If the ratio of the height of a tower and the length of its shadow is ...

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  17. A ladder makes an anglesof 60^(@) with the ground when placed against ...

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  18. The angle of depression of a car parked on the road from the top of th...

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  19. the angle of elevation of the top of a tower at a point on the ground ...

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  20. If x=acostheta and y=bsintheta then b^(2)x^(2)+a^(2)y^(2)= …………. .

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