Home
Class 10
MATHS
How many consecutive odd integers beginn...

How many consecutive odd integers beginning with 5 will sum to 480?

Text Solution

Verified by Experts

The correct Answer is:
20
Promotional Banner

Topper's Solved these Questions

  • SAMPLE PAPER - 2

    FULL MARKS|Exercise PART - III ( Anwer any ten questions. Question is compulsory )|14 Videos
  • SAMPLE PAPER - 2

    FULL MARKS|Exercise PART - IV( Answer all the questions )|2 Videos
  • SAMPLE PAPER - 2

    FULL MARKS|Exercise PART - I ( Choose the correct answer . Answer all the questions )|13 Videos
  • SAMPLE PAPER - 14 (UNSOLVED)

    FULL MARKS|Exercise PART - IV|3 Videos
  • SAMPLE PAPER - 6 (UNSOLVED)

    FULL MARKS|Exercise PART - IV|3 Videos

Similar Questions

Explore conceptually related problems

The arithmetic mean of 7 consecutive integers starting with 'a' is m. Then the arithmetic mean of 11 consecutive integers starting with 'a+2' is

Find all pairs of consecutive odd positive integers both of which are smaller than 10 such that their sum is more than 11.

How many consecutive terms starting from the first term of the scries 2 + 6 + 18 + ... would sum to 728?

If the roots of x^(2)-ax+b=0 are two consecutive odd integers, then a^(2)-4b is

If (1+3+5++p)+(1+3+5++q)=(1+3+5++r) where each set of parentheses contains the sum of consecutive odd integers as shown, the smallest possible value of p+q+r(w h e r ep >6) is 12 b. 21 c. 45 d. 54

Find the pairs of consecutive odd positive intergers both of which are smaller than 10 such that their sum is more than 11.

Take any three consecutive odd numbers and find their product, for example 1 xx 3 xx 5 = 15 , 3 xx 5 xx 7 = 105 , 5 xx 7 xx 9 -..........

Find two consecutive positive odd integers, sum of whose squares is 290.

The fourth power of the common difference of an arithmetic progression with integer entries is added to the product of any four consecutive of it. Prove that the resulting sum is the squares of an integer.