Let: `f:A to B` be a function defined by `f(x)=(x)/(2)-1`. Where `A={2, 4, 6, 10, 12}, B={0, 1, 2, 4, 5, 9}. Represents f by
set of ordered pairs,

Let: f:A to B be a function defined by f(x)=(x)/(2)-1 . Where A={2, 4, 6, 10, 12}, B={0, 1, 2, 4, 5, 9}. Represents f by a table,

Let: f:A to B be a function defined by f(x)=(x)/(2)-1 . Where A={2, 4, 6, 10, 12}, B={0, 1, 2, 4, 5, 9}. Represents f by a graph,

Let: f:A to B be a function defined by f(x)=(x)/(2)-1 . Where A={2, 4, 6, 10, 12}, B={0, 1, 2, 4, 5, 9}. Represents f by an arrow diagram diagram,

A relation 'f' is defined by f(x)=x^(2)-2 where xin{-2, -1, 0, 3} Is f a function?

Let the function f be defined by f(x)={(3x0lexle1),(-3x+51ltxle2):} , then:

Let a function f be defined by f(x)=(x-|x|)/x for x ne 0 and f(0)=2. Then f is

let A = { 1,2,3,4} and B = { 2,5, 8, 11,14} be two sets. Let f : A to B be a function given by f(x) = 3x -1 . Represent this function (i) by arrow diagram (ii) in a table form (iii) as a set of ordered pairs (iv) in a graphical form

If A={-2,-1,0,1,2} and f:A to B is an onto function defined by f(x)=x^(2) +x+1 then find B .