The height and radius of the cone of which the frustum is a part are `h^(1)` units and `r_(1)` units respectively. Height of the frustum is `h_(2)` units and radius of the smaller base is `r_(2)` units. If `h_(2) : h_(1)= 1 : 2 " then " r_(2) : r_(1)` is
A
`1:3`
B
`1:2`
C
`2:1`
D
`3:1`
Text Solution
Verified by Experts
Topper's Solved these Questions
SAMPLE PAPER 17 (UNSOLVED)
FULL MARKS|Exercise PART-I I|14 Videos
SAMPLE PAPER 17 (UNSOLVED)
FULL MARKS|Exercise PART-III|14 Videos
SAMPLE PAPER 16 (UNSOLVED)
FULL MARKS|Exercise PART-IV|1 Videos
SAMPLE PAPER 18 (UNSOLVED)
FULL MARKS|Exercise PART-IV|2 Videos
Similar Questions
Explore conceptually related problems
A spherical ball of radius r_(1) units is melted to make 8 new identical balls each of radius r_(2) units. Then r_(1) : r_(2) is
When the angle of elevation of a gun are 60^(@) and 30^(@) respectively . The heights it shoots are h_(2) and h_(2) respectively . Find the ration h_(2) //h_(2) .
The radii of the bases of two right circular solid cones of same height are r_(1) and r_(2) respectively. The cones are melted and recast into a solid sphere of Radius ''R'' show the height of the cone is given by h=(4R^(3))/(r_(1)^(2)+r_(2)^(2)
A hemispherical solid of radius r_1 units is melted and made into 32 identical spherical balls each of radius r_2 units then r_1 : r_2 is:
What happens to the volume of the cylinder with radius r and height h, when its (a) radius is halved, (b) height is halved.
If I is the incenter of Delta ABC and R_(1), R_(2), and R_(3) are, respectively, the radii of the circumcircle of the triangle IBC, ICA, and IAB, then prove that R_(1) R_(2) R_(3) = 2r R^(2)
