[" Equation of one of the latusrectum of the "],[" hyperbola "]

The equation of the latusrectum of the hyperbola 3y^(2)-4x^(2)=12 are

The equation of the latusrectum of the hyperbola 3y^(2)-4x^(2)=12 are

The equation of the latusrectum of the hyperbola ((x-4)^(2))/(16)-((y-3)^(2))/(20)=1 are

Find the eccentricity foci, equation of the directrices and length of the latusrectum of the hyperbola x^(3) - 4y^(2) = 4

The equation of the latusrectum of the parabola x^2+4x+2y=0 is

The asymptotes of the hyperbola are 3x=+-5y and its vertices are (pm5,0) then the length of latusrectum of the hyperbola is

The asymptotes of the hyperbola are 3x=+-5y and its vertices are (+-5,0) then the length of latusrectum of the hyperbola is

The equation of one of the directrices a hyperbola is 2x+y=1, the corresponding focus is (1,2) and e=sqrt(3). Find the equation of the hyperbola and the cooordinates of the center and the second focus.

The length of the latusrectum of the hyperbola (x^(2))/(a^(2))-(y^(2))/(b^(2))=-1 , is

The length of the latusrectum of the hyperbola (x^(2))/(a^(2))-(y^(2))/(b^(2))=-1 , is