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If tan 40^(@) = lambda, then (tan 140^(@...

If tan `40^(@) = lambda`, then `(tan 140^(@) - tan 130^(@))/(1 + tan 140^(@) tan 130^(@))` =

A

`(1-lambda^(2))/(lambda)`

B

`(1+lambda^(2))/(lambda)`

C

`(1+lambda^(2))/(2lambda)`

D

`(1-lambda^(2))/(2lambda)`

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