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For any two sets A and B, (A-B)cup(B-A)=...

For any two sets `A` and `B`, `(A-B)cup(B-A)=`

A

`(A-B)cupA`

B

`(B-A)cupB`

C

`(AcupB)-(AcapB)`

D

`(AcupB)cap(AcapB)`

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