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cos 2theta cos 2phi + sin^(2) (theta - p...

cos `2theta cos 2phi + sin^(2) (theta - phi ) - sin^(2) ( theta + phi)` is equal to

A

`sin2 (theta+phi)`

B

`cos2(theta+phi)`

C

`sin2(theta-phi)`

D

`cos2(theta-phi)`

Text Solution

Verified by Experts

The correct Answer is:
B
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