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Find the value of tan 315^o cot(-405^o)+...

Find the value of `tan 315^o cot(-405^o)+cot495^o tan(-585^o)`

Text Solution

Verified by Experts

The correct Answer is:
L.H.S=`tan(360^o-45^o)[-cot(360^(o)+45^o)]+cot(360^(o)+135^o)[-tan(360^(o)+225^o]`
`=[-tan45^o][-cot45^o]+[tan45^o][-tan45^o]=(-1)(-1)+(-1)(-1)=2`
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Prove that tan 315^(@) cot ( -405^(@) ) + cot 495^(@) tan (-585^(@)) = 2