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Without expanding the determinant prove ...

Without expanding the determinant prove that `|[s,a^(2),b^(2)+c^(2)],[s,b^(2),c^(2)+a^(2)],[s,c^(2),a^(2)+b^(2)]|=0`

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The correct Answer is:
`|[s,a^2,b^2+c^2],[s,b^2,c^2+a^2],[s,c^2,a^2+b^2]|=|[s,a^2,a^2+b^2+c^2],[s,b^2,a^2+b^2+c^2],[s,c^2,a^2+b^2+c^2]|(c_3toc_3+c_2)`
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