Home
Class 11
MATHS
A committee of 7 peoples has to be forme...

A committee of 7 peoples has to be formed from 9 men and 4 women . In how many can this be done when then committee consists of
(i) exactly 3 women ?
(ii) at least 3 woman ?
(iii) at most 3 women ?

Text Solution

Verified by Experts

The correct Answer is:
(i) =504, (ii) =504+84=588, (iii) = 36+336+756+504=1632
Promotional Banner

Topper's Solved these Questions

  • COMBINATORICS AND MATHEMATICAL INDUCTION

    FULL MARKS|Exercise EXERCISE 4.5|25 Videos
  • BINOMIAL THEOREM, SEQUENCES AND SERIES

    FULL MARKS|Exercise Additional Questions Solved|31 Videos
  • DIFFERENTIAL CALCULUS - DIFFERENTIABILITY AND METHODS OF DIFFERENTIATION

    FULL MARKS|Exercise EXERCISE 5 ADDITIONAL PROBLEMS (Find the derivative of following functions.)|10 Videos

Similar Questions

Explore conceptually related problems

A committee of 7 peoples has to be formed from 8 men and 4 women. In how many ways can this be done when the committee consists of Q exactly 3 women

A committee of 7 peoples has to be formed from 8 men and 4 women. In how many ways can this be done when the committee consists of Q at least 3 women?

A committee of 3 persons is to be constituted from a group of 2 men and 3 women. a. In how many ways can this be done? b. How many of these committees would consist of 1 man and 2 women?

A committee of 6 is to be choosen from 10 men and 7 women so as to contain atleast 3 men and 2 women. In how many different ways can this be done?

A committee of 5 persons is to be formed from 7 men and 3 women. i. Find the number of ways to form the committee so that it contains 5 men. ii. Find the number of ways to form the committee so that it contains 4 men and 1 women. iii. Find the number of ways to form the committee so that it contains atleast 1 women.

In how many ways can a committee of 3 men and 2 women be selected out of 7 men and 5 women?

FULL MARKS-COMBINATORICS AND MATHEMATICAL INDUCTION-ADDITIONAL QUESTIONS
  1. How many words, with or without meaning , can be made from the letters...

    Text Solution

    |

  2. A group consists of 4 girls and 7 boys. In how many ways can a team of...

    Text Solution

    |

  3. A committee of 6 is to be choosen from 10 men and 7 women so as to con...

    Text Solution

    |

  4. Using the digits 1,2,3,4,5,6,7 a number of 4 different digits is forme...

    Text Solution

    |

  5. If ""^(22)P(r+1):^(20)P(r+2)=11:52, find r.

    Text Solution

    |

  6. If ""^(nP(r)=""^(n)P(r+1) and ""^(n)C(r)=""^(n)C(r-1) find n and r.

    Text Solution

    |

  7. A committee of 7 peoples has to be formed from 9 men and 4 women . In ...

    Text Solution

    |

  8. In .^(2n)C(3) :.^(n)C(3) = 11 : 1 then n is

    Text Solution

    |

  9. Find the number of ways of selecting 9 balls from 6 red balls, 5 white...

    Text Solution

    |

  10. If 1/(7!)+1/(9!)=x/(10!), find x.

    Text Solution

    |

  11. If ""^(n)C(4),^(n)C(5)" and "^(n)C(6) are in A.P. then find n.

    Text Solution

    |

  12. Prove by induction the inequality (1+x)^(n) ge 1 + nx. whenever x is p...

    Text Solution

    |

  13. Prove that 3^(2n)-1 is divisible by 8.

    Text Solution

    |

  14. Prove that x^n-y^n is divisible by x - y for all positive integers n.

    Text Solution

    |

  15. Prove by mathematical induction that for every natural number n, 3^(2n...

    Text Solution

    |

  16. Use the principle of mathematical induction to prove that for every na...

    Text Solution

    |

  17. n^(3)-n is divisible by 6, for each natural number n ge 2

    Text Solution

    |

  18. Prove that For any natural number n, 7^n - 2^n is divisible by 5.

    Text Solution

    |

  19. Find (10!)/(5!" X "2!)

    Text Solution

    |

  20. Compute 10C1

    Text Solution

    |