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Show that int(0)^(pi) g (sinx)dx=2 int(0...

Show that `int_(0)^(pi) g (sinx)dx=2 int_(0)^((pi)/(2))g(sin)dx`, where `g(sinx)` is a function of `sinx`.

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The correct Answer is:
`int_(0)^(pi)g(sinx)dx=2int_(0)^(pi/2)g(sinx)dx`
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