In a binomial distribution consisting of 5 independent trials the probability of 1 and 2 sucesses are 0.4096 and 0.2048 respectively. Find the mean and variance of the distribution .

In a binomial distrubution consisting of 5 independent trials the probability of 1 and 2 successers are 0.4096 and 0.2048 respectively find the mean and variance of the random variable

Find the mean and variance for the frequency distribution.

Mean and variance of binomial distribution are.

In a binomial distribution with mean 4 and variance 16/5 then p is

In a binomial distribution if n =5 P(X=3)=2(PX=2)then

Find the mean of the Binomial distribution B (4, (1)/(3))

In a Binomial distribution if n = 5 and P(X=3) =2P (X=2) find p.

In a binomial distribution, n=4, P(X=0)=16/81 , then P(X=4).