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If R = {(x', y): x in W, Y in W and (x ...

If `R = {(x', y): x in W, Y in W` and `(x + 2y)^(2) = 36}` then `R^(-1)` is__________. (a) `{(0, 3), (2,3), (1,4), (0, 6)}` (b) `{(0,6),(0,3),(2,2), (4,1)}` (c) `{(3,0), (2,2), (1,4), (0,6)}` (d) `{(3,0), (2,2),(1,4), (6,0)}`

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To solve the problem step by step, we need to find the relation \( R \) defined by the equation \( (x + 2y)^2 = 36 \) where \( x \) and \( y \) are whole numbers. Then we will find the inverse of the relation \( R^{-1} \). ### Step 1: Solve the equation for \( y \) We start with the equation: \[ (x + 2y)^2 = 36 \] Taking the square root of both sides gives us: ...
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