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If A=(1,2) and B=(2,3), then find the nu...

If `A=(1,2)` and B=(2,3), then find the number of elements in `(AxxB)cap(BxxA)`. The following are the steps involved in solving the above problem. Arrange them in sequential order.
(A) `(AxxB)cap(BxxA)=(2,2)`
(B) Given `A=(1,2)` and B=(2,3)
(C) `n[)AxxB)cap(BxxA)]=1`
(D) `AxxB={(1,2)(1,3)(2,2)(2,3)}` and `B xxA={(2,1),(2,2),(#,1),(3,2)}`

A

BADC

B

BDCA

C

BCAD

D

BDAC

Text Solution

Verified by Experts

The correct Answer is:
D
The sequential order is CABD.
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