A piece of work can be done by 16 man in 8 days working 12 hours a day. How many men ar needed to complete another work,which is three times the first one, in 24n days working 8 hourse, a day?

Explanation

Using the formula, `(M_(1)D_(1)H_(1))/(W_(1))=(M_(2)D_(2)H_(2))/(W_(2))`
Let `W_(1)=x and W_(2)=3x`
`M_(1)=16,H_(1)=12,D_(1)=8`
`H_(2)=8,D_(2)=24`
`:.(16xx8xx12)/(x)=(M_(2)xx24xx8)/(3x)`
`rArrM_(2)=24`
`:.` Requrired numbrer of men is 34