A can do a work in x days and B can do the same work in y days. If `xgty` , then who can do more work in 6 days?

Answer

To solve the problem, we need to determine how much work A and B can complete in 6 days, given that A can complete the work in x days and B can complete the same work in y days, with the condition that x > y.

### Step-by-Step Solution:

1. **Determine the work done by A in one day:**
- Since A can complete the work in x days, the fraction of the work A can do in one day is:
\[ \text{Work done by A in 1 day} = \frac{1}{x} \]

2. **Calculate the work done by A in 6 days:**
- To find out how much work A can do in 6 days, we multiply the work done in one day by 6:
\[ \text{Work done by A in 6 days} = 6 \times \frac{1}{x} = \frac{6}{x} \]

3. **Determine the work done by B in one day:**
- Since B can complete the work in y days, the fraction of the work B can do in one day is:
\[ \text{Work done by B in 1 day} = \frac{1}{y} \]

4. **Calculate the work done by B in 6 days:**
- To find out how much work B can do in 6 days, we multiply the work done in one day by 6:
\[ \text{Work done by B in 6 days} = 6 \times \frac{1}{y} = \frac{6}{y} \]

5. **Compare the work done by A and B in 6 days:**
- We need to compare \(\frac{6}{x}\) and \(\frac{6}{y}\). Since x > y, we know that:
\[ \frac{1}{x} < \frac{1}{y} \]
- Therefore, multiplying both sides by 6 (which is positive) gives:
\[ \frac{6}{x} < \frac{6}{y} \]

6. **Conclusion:**
- Since \(\frac{6}{x} < \frac{6}{y}\), it follows that B can do more work than A in 6 days.

### Final Answer:
B can do more work in 6 days.