f(x)={[e^(-(1)/(x)),,x!=0],[0,x=0]" at "x=0

Discuss the differentiability of: f(x)={[x(e^x-1)/(e^x+1),x!=0],[0,x=0]:} at x=0

Examine continuity and differentiability f(x)={[(1-e^(-x))/x,x!=0],[1,x=0]:} at x=0.

Let f(x)={[((e^(3x)-1))/(x),,x!=0],[3,,x=0]} then 2f'(0) is

If f(x)={(1)/(e^((1)/(x))+1),x!=0,0,x=0 then

The function f(x)={(e^(1/x)-1)/(e^(1/x)+1),x!=0, at x=0 ,f(x)=0 a. is continuous at x=0 b. is not continuous at x=0 c. is not continuous at x=0, but can be made continuous at x=0 (d) none of these

If f(x)={(x)/(e^((1)/(x))+1),x!=0 and 0,x=0

Check the continuity of the following functions: f(x){(1)/(1-e^((1)/(x))),x!=0 and 0,x=0

if f(x)=e^(-(1)/(x^(2))),x!=0 and f(0)=0 then f'(0) is

Examine for continuity, the function 'f' defined by f(x) = {:{(e^(1//x), x ne 0),(0,x=0):} at x = 0

if f(x)=e^(-(1)/(x^(2))),x>0 and f(x)=0,x<=0 then f(x) is