" S.If "pi<=x<=2 pi" and "y=cos^(-1)(cos x)," find "(dy)/(dx)

For sets S= { pi, pi^(2) , pi^(3) } and T= {e, e^(2) , e^(3) } if F^(-1) : T to S is defined as F^(-1) = { ( e, pi^(3) ) , (e^(2) , pi^(2) ), (e^(2) , pi)} , then function F=.........

The phase of a particle in S.H.M. is pi//2 , then :

Column I, Column II Range of f(x)=sin^(-1)x+cos^(-1)x+cot^(-1)xi s , p. [0,pi/2]uu[pi/2,pi] Range of f(x)= cot^(-1)x+tan^(-1)x+cos e c^(-1)xi s , q. [pi/2,(3pi)/2] Range of f(x)=cot^(-1)x+tan^(-1)x+cos^(-1)xi s , r. [0,pi] Range of f(x)= sec^(-1)x+cos e c^(-1)x+sin^(-1)xi s , s. [(3pi)/4,(5pi)/4]

Column I, Column II Range of f(x)=sin^(-1)x+cos^(-1)x+cot^(-1)xi s , p. [0,pi/2]uu[pi/2,pi] Range of f(x)= cot^(-1)x+tan^(-1)x+cos e c^(-1)xi s , q. [pi/2,(3pi)/2] Range of f(x)=cot^(-1)x+tan^(-1)x+cos^(-1)xi s , r. [0,pi] Range of f(x)= sec^(-1)x+cos e c^(-1)x+sin^(-1)xi s , s. [(3pi)/4,(5pi)/4]

In Figure, O A B C is a square of side 7 cm. If O A P C is a quadrant of a circle with centre O , then find the area of the shaded region. (U s e\ \ pi=22//7)

The outer circumference of a circular race-track is 528 m. The track is everywhere 14 m wide. Calculate the cost of levelling the track at the rate of 50 paise per square metre (U s e\ \ pi=22//7) .

The radius and slant height of a cone are in the ratio of 4:7. If its curved surface area is 792\ c m^2, find the radius. (U s e\ pi=(22)/7)

The radius and slant height of a cone are in the ratio of 4:7. If its curved surface area is 792\ c m^2, find the radius. (U s e\ pi=(22)/7)

The radius and the height of a right circular cone are in the ratio 5:12. If its volume is 314 cubic metre, find the slant height and the radius (U s e\ pi=3. 14)