" If "A=[[cos theta,sin theta],[-sin theta,cos theta]]," then "A*A

" (1) "|[cos theta,-sin theta],[sin theta,cos theta]|

Show that if A = [[cos theta, sin theta],[-sin theta, cos theta]] , then A^n = [[cos n theta, sin n theta],[-sin n theta, cos n theta]]

If A = [[cos theta, sin theta],[-sin theta, cos theta]] , then what is A^(-1) ?

If A= [[cos theta,-sin theta],[sin theta,cos theta]] ,then Adj A is (a) [[cos theta,-sin theta],[cos theta,sin theta]] (b) [[1,0],[0,1]] (c) [[cos theta,sin theta],[-sin theta,cos theta]] (d) [[-1,0],[0,-1]]

The inverse of A=[[cos theta, sin theta],[-sin theta,cos theta]] is :

If A=[[cos theta,sin theta],[-sin theta,cos theta]] and A(adj A)=[[k,0],[0,k]] , then k =

If A=[(-cos theta, sin theta),(sin theta, cos theta)] then IAI=

If E(theta)=[[cos theta, sin theta] , [-sin theta, cos theta]] then E(alpha) E(beta)=

If E(theta)=[[cos theta, sin theta] , [-sin theta, cos theta]] then E(alpha) E(beta)=