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[x+2y=(3)/(2)],[2x+y=(3)/(2)]...

[x+2y=(3)/(2)],[2x+y=(3)/(2)]

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Solve the following system of equations: x+2y=(3)/(2),quad 2x+y=(3)/(2)

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The solution of (x^(2)y^(3) +x^(2))dx + (y^(2)x^(3)+y^(2))dy = 0 is

The equation of the transvers and conjugate axes of a hyperbola are,respectively,x+2y-3=0 and 2x-y+4=0, and their respective lengths are sqrt(2) and 2sqrt(3) .The equation of the hyperbola is (2)/(5)(x+2y-3)^(2)-(3)/(5)(2x-y+4)^(2)=1(2)/(5)(x-y-3)^(2)-3(x+2y-3)^(2)=12(x+2y-3)^(2)-3(2x-y+4)^(2)=1