If `a = 1 + "log"_(x) yz, b = 1 + "log"_(y) zx, c =1 + "log"_(z) xy,` then ab+bc+ca =

If x = 1 + log_(a) bc, y = 1 + log_(b) ca, z = 1 + log_(c) ab, then xy + yz + zx =

If x ="log"_(a)(bc), y ="log"_(b)(ca) " and "z = "log"_(c)(ab), then which of the following is correct?

If x ="log"_(a)(bc), y ="log"_(b)(ca) " and "z = "log"_(c)(ab), then which of the following is correct?

If x = log_(a) bc, y = log_(b) ca, z = log_(c) ab, then the value of (1)/(1 + x) + (1)/(1 + y) + (1)/(l + z) will be

If a=log_(x)(yz),b=log_(y)(zx),c=log_(z)(xy) where x,y,z are positive reals not equal to unity,then abc-a-b-c is equal to

If ("log"_(e)x)/(b - c) = ("log"_(e) y)/(c - a) = ("log"_(e) z)/(a - b) , show that x^(a)y^(b)z^(c ) = 1

If ("log"_(e)x)/(b - c) = ("log"_(e) y)/(c - a) = ("log"_(e) z)/(a - b) , show that xyz = 1

If x=1+log_(a) bc, y=1+log_(b) ca, z=1+log_(c) ab , then (xyz)/(xy+yz+zx) is equal to