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[sin3A-cos((pi)/(2)-A)=],[(cos A+cos(pi+...

[sin3A-cos((pi)/(2)-A)=],[(cos A+cos(pi+3A))/(1)tan A)quad " 2) cot "Aquad " 3) "t]

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(sin 3A -cos ((pi)/(2)-A))/(cos A+ cos (pi+3A))=

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(sin 3A -cos ((pi)/(2)-A))/(cos A+ cos (pi+3A))= ................. A) tan A B) cot A C) tan 2A D) cot 2A

cos ((3pi )/( 2 ) + x) cos (2pi + x) [cot ((3pi)/( 2)- x ) + cot (2pi +x) ]=1

cos ((3pi )/( 2 ) + x) cos (2pi + x) [cot ((3pi)/( 2)- x ) + cot (2pi +x) ]=1

cos ((3pi )/( 2 ) + x) cos (2pi + x) [cot ((3pi)/( 2)- x ) + cot (2pi +x) ]=1

Prove that cos ( ( 3pi )/(2) + x) ) cos (2pi+x) .[ cot ((3pi )/( 2) - x) ) + cot (2pi +x) ]=1

The expression (tan(x-(pi)/(2))cos((3 pi)/(2)+x)-sin^(3)((7 pi)/(2)-x))/(cos(x-(pi)/(2))tan((3 pi)/(2)+x)) is equal to

cos((3pi)/(2) +x) cos(2pi+x)[cot(3pi)/(2)-x+cot(2pi+x)]=1

4sin ((pi) / (6)) sin ^ (2) ((pi) / (3)) + 3cos ((pi) / (3)) tan ((pi) / (4)) + cos e ^ ( 2) ((pi) / (2)) = 2sec ^ (2) ((pi) / (4))