Calculate the vapour pressure lowering caused by the addition of `68.4 g` of sucrose (molecular mass = 342) to `500 g` of water if the vapour pressure of pure water at `25^(@)C` is `20.0 mm Hg`.

Calculate the vapour pressure lowering caused by addition of 50g of sucrose (molecular mass = 342) to 500g of water if the vapour pressure of pure water at 25^(@)C is 23.8 mm Hg .

Calculate the vapour pressure lowering caused by addition of 50g of sucrose (molecular mass = 342) to 500g of water if the vapour pressure of pure water at 25^(@)C is 23.8 mm Hg .

Calculate the vapour pressure lowering caused by addition of 50g of sucrose (molecular mass = 342) to 500g of water if the vapour pressure of pure water at 25^(@)C is 23.8 mm Hg .

The vapour pressure lowering caused by the addition of 100 g of sucrose (molecular mass = 342) to 1000 g of water, if the vapour pressure of pure water at 25^@C is 23.8 mm Hg, is

The vapour pressure lowering caused by addition of 100 g of sucrose (molecular mass = 342) to 1000 g of wate,if the vapour pressure of pure water at 25^(@)C is 23.8mm Hg,is

The vapour pressure lowering caused by addition of 100 g of sucrose (molecular mass = 342) to 1000 g of wate,if the vapour pressure of pure water at 25^(@)C is 23.8mm Hg,is

Calculate the lowering of vapour pressure caused by addition of 100 g of sucrose (molecular mass -342) to 1 kg of water if the vapour pressure of water at 25^@C is 23.8 mm in mercury.

6.0 g of urea (molecular mass = 60) was dissolved in 9.9 moles of water. If the vapour pressure of pure water is P^(@) , the vapour pressure of solution is :

Vapour pressure in mm Hg of 0.1 mole of urea in 180 g of water at 25^(@)C is (The vapour pressure of water at 25^(@) C is 24 mm Hg)

What do you mean by relative lowering of vapour pressure? Calculate the relative lowering of Vapour pressure of a solution formed by dissolving 50 g of urea (NH_2 CONH_2) in 850g of water.(Given vapour pressure of pure water at 298K= 23.8mm of Hg.)