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The equation of the circle having radius...

The equation of the circle having radius 3 and touching the circle `x^(2) + y^(2)-4x -6y - 12 = 0` at (-1,-1) is

A

`5x^(2)+5y^(2)+8x - 14y - 16 =0`

B

`5x^(2)+5y^(2)-8x - 14y - 32 =0`

C

`5x^(2)+5y^(2)-8x + 14y - 4 =0`

D

`5x^(2)+5y^(2)-8x + 14y + 12 =0`

Text Solution

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The correct Answer is:
B
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KCET PREVIOUS YEAR PAPERS-MODEL TEST PAPER - 8-MATHEMATICS
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  15. If vecp = veca - vecb , vecq = vec a + vec b and |veca| = |vecb| = 2 ...

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