Home
Class 11
MATHS
The function f : [0,2pi] to 1 [-1,1] def...

The function f : [0,2`pi] to 1` [-1,1] defined by f(x) = sin x is

Promotional Banner

Similar Questions

Explore conceptually related problems

The functions f:[-1//2, 1//2] to [-pi//2, pi//2] defined by f(x)=sin^(-1)(3x-4x^(3)) is

Function f : [(pi)/(2), (3pi)/(2)] rarr [-1, 1], f(x) = sin x is

Function f : [(pi)/(2), (3pi)/(2)] rarr [-1, 1], f(x) = sin x is

let A={x:-(pi)/(2) le x le (pi)/(2)} and B={x:-1 le x le 1} . Show that the function f: A rarr B defined by, f(x)= sin x for all x in A , is bijective . Hence, find a formula that defines f^(-1)

Let a function f:R to R be defined as f (x) =x+ sin x. The value of int _(0) ^(2pi)f ^(-1)(x) dx will be:

Let a function f:R to R be defined as f (x) =x+ sin x. The value of int _(0) ^(2pi)f ^(-1)(x) dx will be:

If the function f:[1,oo)to[1,oo) is defined by f(x)=2^(x(x-1)) then f^(-1) is