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Rate of normal flow of heat in Searle's ...

Rate of normal flow of heat in Searle's method for thermal conductivity is

A

`Q//t = (KA d)//(theta_1-theta_2)`

B

`Q//t = Ka (theta_1 - theta_2)//d`

C

`Q//t = K(theta_1-theta_2)//Ad`

D

`Q//t = KA //[d(theta_1 - theta_2)]`

Text Solution

Verified by Experts

The correct Answer is:
b
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